Convert Rankine to Fahrenheit & Other Temperature Units

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📝 Temperature Units & Formulas

UnitFormulaValue
Celsius, °C°C = °R x 5/9 – 273,150 °R = -273,15 °C
Kelvin, KK = °R x 5/90 °R = 0 K
Fahrenheit, °F°F = °R – 459,670 °R = -459,67 °F
Réaumur, °Ré°Ré = (°R x 5/9 – 273,15) x 0,80 °R = -218,52 °Ré
Newton, °N°N = (°R x 5/9 – 273,15) x 0,330 °R = -90,1395 °N
Delisle, °De°De = (373,15 – (°R x 5/9)) x 3/20 °R = 559,725 °De
Rømer, °Ro°Ro = (°R x 5/9 – 273,15) x 21/40 + 7,50 °R = -135,9 °Ro

🔁 Rankine Conversion Examples

Convert Rankine to Celsius

  • 1 °R x 5/9 – 273,15 = -272,59 °C
  • 10 °R x 5/9 – 273,15 = -267,59 °C

Convert Rankine to Kelvin

  • 1 °R x 5/9 = 0,17 K
  • 10 °R x 5/9 = 5,55 K

Convert Rankine to Fahrenheit

  • 1 °R – 459,67 = -458,67 °F
  • 10 °R – 459,67 = -449,67 °F

Convert Rankine to Réaumur

  • (1 °R x 5/9 – 273,15) x 0,8 = -218,08 °Ré
  • (10 °R x 5/9 – 273,15) x 0,8 = -214,08 °Ré

Convert Rankine to Newton

  • (1 °R x 5/9 – 273,15) x 0,33 = -89,95 °N
  • (10 °R x 5/9 – 273,15) x 0,33 = -88,31 °N

Convert Rankine to Delisle

  • (373,15 – (1 °R x 5/9)) x 3/2 = 558,9 °De
  • (373,15 – (10 °R x 5/9)) x 3/2 = 551,4 °De

Convert Rankine to Rømer

  • (1 °R x 5/9 – 273,15) x 21/40 + 7,5 = -135,6 °Ro
  • (10 °R x 5/9 – 273,15) x 21/40 + 7,5 = -132,987 °Ro

✅ Rankine to Fahrenheit Converter FAQ

✔️ How to convert °R to °C?

If you need to convert degrees Rankine (°R) to degrees Celsius (°C), you can use the following formula: °C = °R x 5/9 – 273,15. In other words, you need to multiply your value in degrees Rankine by 5/9 and then subtract 273,15 from it.

✔️ What is the formula to change °R into °F?

In order to convert degrees Rankine to Fahrenheit, you can use the following formula: °F = °R – 459.67. In other words, to get degrees in Fahrenheit, all you need to do is subtract 459.67 from your value in degrees Rankine.

✔️ Is 40°R hot or cold?

40 degrees Rankine, which is -250 degrees Celsius and –420 degrees Fahrenheit, is considered to be extremely cold. 40°R is far below the freezing point of water. Moreover, such a temperature cannot be found in natural conditions on Earth.